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Oracle 1Z0-007 Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|---|---|
| Single-Row Functions | 18% | - Conditional expressions (NVL, DECODE) - Conversion functions (TO_CHAR, TO_NUMBER, TO_DATE) - Character, number, and date functions |
| Aggregating Data Using Group Functions | 13% | - GROUP BY clause - Using COUNT, SUM, AVG, MAX, MIN - Filtering groups with HAVING |
| Writing Basic SQL SELECT Statements | 15% | - SQL vs iSQL*Plus commands - Capabilities of SQL SELECT statements - Executing basic SELECT statements |
| Restricting and Sorting Data | 12% | - Limiting rows with WHERE clause - Sorting results with ORDER BY - Using substitution variables |
| Displaying Data from Multiple Tables | 15% | - Equijoins and non-equijoins - ANSI/ISO SQL99 joins - Outer joins and self-joins |
| Subqueries | 10% | - Using IN, ANY, ALL operators - Single-row and multi-row subqueries |
| Creating and Managing Tables | 9% | - Data types and constraints - CREATE, ALTER, DROP, RENAME tables - Managing indexes, sequences, synonyms, views |
| Manipulating Data | 8% | - Transaction control (COMMIT, ROLLBACK, SAVEPOINT) - INSERT, UPDATE, DELETE statements |
Oracle Introduction to Oracle9i: SQL Sample Questions:
Question 1
Which statement adds a constraint that ensures the CUSTOMER_NAME column of the CUSTOMERS table holds a value?
A. ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name NOT NULL;
B. ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn NOT NULL;
C. ALTER TABLE customers MODIFY CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;
D. ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn IS NOT NULL;
E. ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;
F. ALTER TABLE customers MODIFY name CONSTRAINT cust_name_nn NOT NULL;
Question 2
What is necessary for your query on an existing view to execute successfully?
A. You need SELECT privileges on the view.
B. You need SELECT privileges only on the underlying tables.
C. The underlying tables must have data.
D. The underlying tables must be in the same schema.
Question 3
Which statement describes the ROWID data type?
A. Character data up to 4 gigabytes.
B. Raw binary data of variable length up to 2 gigabytes.
C. Binary data up to 4 gigabytes.
D. Binary data stored in an external file, up to 4 gigabytes.
E. A hexadecimal string representing the unique address of a row in its table.
Question 4
Examine the description of the CUSTOMERS table:
The CUSTOMER_ID column is the primary key for the table.
Which statement returns the city address and the number of customers in the cities Los Angeles or San Francisco?
A. SELECT city_address, COUNT(customer_id)
FROM customers
WHERE city_address IN ( 'Los Angeles', 'San Fransisco')
GROUP BY city_address, customer_id;
B. SELECT city_address, COUNT (customer_id)
FROM customers
GROUP BY city_address IN ( 'Los Angeles', 'San Fransisco');
C. SELECT city_address, COUNT(*)
FROM customers
WHERE city_address IN ( 'Los Angeles', 'San Fransisco');
D. SELECT city_address, COUNT (*)
FROM customers
WHERE city address IN ( 'Los Angeles', 'San Fransisco')
GROUP BY city_address;
Question 5
Which two statements about creating constraints are true? (Choose two)
A. Information about constraints is found in the VIEW_CONSTRAINTS dictionary view.
B. Constraint names must start with SYS_C.
C. Constraints can be created after the table is created.
D. All constraints must be defines at the column level.
E. Constraints can be created at the same time the table is created.
Solutions:
| Question 1 Answer: B | Question 2 Answer: A | Question 3 Answer: E | Question 4 Answer: D | Question 5 Answer: C,E |



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