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IBM C6030-041 Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|---|---|
| Topic 1: PL/I Language Fundamentals | 25% | - Scope and visibility - Expressions and operators - Data types and attributes
|
| Topic 2: Input/Output and File Handling | 15% | - Environment options and z/OS integration - File declarations and attributes - Record and stream I/O |
| Topic 3: Control Structures and Program Flow | 20% | - Conditional statements - Procedures, functions, and entry points - Iteration and looping - Parameter passing mechanisms |
| Topic 4: Data Structures, Pointers, and Memory Management | 20% | - Controlled and automatic variables - Pointer and based variables - Dynamic storage allocation - Structures, unions, and arrays |
| Topic 5: Compilation, Preprocessing, and Performance | 10% | - Optimization and best practices - Compiler options and directives - Macro and SQL preprocessors |
| Topic 6: Error Handling and Conditions | 10% | - ON units and condition handling - Error recovery and program termination |
IBM Programming with IBM Enterprise PL/I Sample Questions:
Question 1
Given the following program, which subroutine improperly uses pointers to address memory and could lead to data corruption or an exception?
A. SUB2
B. SUB4
C. PROC OPTIONS(MAIN);
DCL
1 X,
2 X1 CHAR(76),
2 X2 PIC'9999';
DCL Y CHAR(20);
CALL SUB1( ADDR(X));
CALL SUB2( ADDR(X));
CALL SUB3( ADDR(X));
CALL SUB4( ADDR(X));
SUB 1: PROC( P);
DCL P POINTER;
DCL
1 XBASED(P),
2 X1 CHAR(76),
2 X2 PIC'9999'
X = ";
END;
SUB2: PROC( P);
DCL P POINTER;
DCL
1 X BASED(P),
2 X 1 PIC'(76)X'
2 X 2 PIC'9999'
X = ";
END;
SUB3: PROC( P);
DCL P POINTER;
DCL X CHAR(60) BASED(P);
X = ";
END;
SUB4: PROC( P );
DCL P POINTER;
DCLX CHAR(100) BASED(P);
X = ";
END; END;
D. SUB1
E. SUB3
Question 2
CORRECT TEXT
Under default condition enablement, what is the result of executing the following code?
DCL A CHAR(5);
A = '123ABC';
A. A will have a value '23ABC'.
B. STRINOSIZE would be raised.
C. A will have a value '123AB'.
D. CONVERSION would be raised.
Question 3
CORRECT TEXT
Given the following code, what will be output?
MP: PROC OPTIONS(MAIN);
DCL A CHAR(1) INIT('A');
DCL B CHAR(1) INIT('B');
DCL C CHAR(1) STATIC INIT('C');
CALL SR1(A);
PUT SKIP LIST(A!!B!!C);
SR1: PROC(A);
DCL A CHAR(1);
DCL B CHAR(1);
DCL C CHAR(1);
A = '1'
B = '2'
C = '3';
END SR1;
END;
A. 1B3
B. 123
C. 12C
D. 1BC
Question 4
CORRECT TEXT
Given the following code, what value will be output?
TEST: PROC OPTIONS(MAIN);
DCL
P POINTER,
N1 FIXED BIN(31),
1 A BASED(P),
2 A1 FIXED BIN(3i),
2 A2 FIXED BIN(3i),
2 A3 FIXED BIN(3i),
2 A4( N1 REFER(A3)) CHAR(10) VAR;
N1 = 5;
ALLOC A;
PUT SKIP LIST( STG(A)); END;
A. 24
B. 62
C. 72
D. 22
Question 5
CORRECT TEXT
What should be done, if anything, when the following compiler message appears?
Multiple closure of blocks, one extra END statement assumed.
A. Take out the extra END statement.
B. PUT an extra END statement at the end of the program.
C. Find the missing END statement and add it at the right place.
D. Nothing needs to be done.
Solutions:
| Question 1 Answer: E | Question 2 Answer: C | Question 3 Answer: D | Question 4 Answer: C | Question 5 Answer: C |



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